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Source：http://www.flowxgroup.com/Update Time：2014-07-23Hits：

**Pneumatic actuators** are existed widespread in domain for repetitive motion in the manipulation of objects. Whether that object is being pushed or pulled, that pneumatic actuators must have adequate force in order to efficiently move the object. All air pressure is measured in pounds per square inch (PSI), and by following a fundamental process you can calculate the entire force that pneumatic actuator carrying higher loads can deliver.

Instructions

1.Measure the size of the pneumatic actuators to compute the whole area that the air will be pushing against to produce the force. All pneumatic actuators are sorted by the diameter of the pneumatic actuators and the length of the stroke. The most vital measurement we require in calculating force is the diameter of the cylinder.

2.Discover the entire area in the pneumatic actuators if the diameter of them is 4 inches. To find the region of a circle for any substance, the formula is A= (pi) x (Rsquared). Where A is equal to area, pi stands for 3.1416 and Rsquared represents the radius of the circle squared.

3.Calculate the region of the 4-inch diameter round circle by first multiplying the radius times itself. This would represent 2 inches as the radius, times itself or 2 X 2 lead to 4. Then multiply pi (3.1416) times the 4 and get the figure 12.5664 square inches as a result. So the total area of the pneumatic **electric actuators** can be 12.5664 inches^2, read as inches squared.

4.Discover the entire force from the pneumatic actuators if the air pressure reaches 100 PSI. Since PSI stands for pounds per square inch, all we require to do is to multiply the entire region in square inches of the pneumatic actuators times the air pressure in PSI. The entire force delivered from the 4-inch diameter pneumatic actuators with 100 PSI of air pressure would reach 12.5664 inches^2 times 100 PSI, which means 1,256.4 pounds of force.

5.Understand that the 1,256.4 pounds of force would be only on the push stroke and not on the revocation end of the pneumatic actuators. The diameter of the push rod must be subtracted from the whole area, as the connection of the push rod intervenes with the force measurement.

6.Discover the region of the push rod for the revocation force measurement if the push rod is 2 inches in diameter. Adopting the formula from Step 3, the region of the push rod would be A = (3.1416) times 1^2, which represents 3.1416 square inches. 3.1416 is subtracted from 12.5664 and the resultant area on the revocation stroke of the pneumatic actuators would be equal to 9.4248 square inches. If the air pressure maintains the same, at 100PSI, then the force would be equal to 942.48 pounds of force.

Tips & Warnings

Any size pneumatic actuators can be computed using the above formula. This involves hydraulic cylinders, as well. You only need to know the entire pressure that the hydraulic system will pass to the cylinder.

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